2[3x-(4x-1)]=8x

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Solution for 2[3x-(4x-1)]=8x equation:


Simplifying
2[3x + -1(4x + -1)] = 8x

Reorder the terms:
2[3x + -1(-1 + 4x)] = 8x
2[3x + (-1 * -1 + 4x * -1)] = 8x
2[3x + (1 + -4x)] = 8x

Reorder the terms:
2[1 + 3x + -4x] = 8x

Combine like terms: 3x + -4x = -1x
2[1 + -1x] = 8x
[1 * 2 + -1x * 2] = 8x
[2 + -2x] = 8x

Solving
2 + -2x = 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
2 + -2x + -8x = 8x + -8x

Combine like terms: -2x + -8x = -10x
2 + -10x = 8x + -8x

Combine like terms: 8x + -8x = 0
2 + -10x = 0

Add '-2' to each side of the equation.
2 + -2 + -10x = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -10x = 0 + -2
-10x = 0 + -2

Combine like terms: 0 + -2 = -2
-10x = -2

Divide each side by '-10'.
x = 0.2

Simplifying
x = 0.2

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